用静态栈数据结构实现表达式求值[12]

                    popop(opstack,&c);

                    popnum(numstack,&b);

                    popnum(numstack,&a);

                    pushnum(numstack,calc(a,b,c));flags=1;

                    process(numstack,opstack,x);break;

            case '=':popop(opstack,&c);flags=1;break;

            default:printf("wrong express!");exit(0);

        }

    }

}

//main函数

main(){