prior->link = p->link;
current = p->link;
delete p;
return ture;
}
else return false;
}
bool removeafter()//删除当前节点的下一个节点,不改变current
{
if (current->link != null && current != null)
{
node<type> *p = current->link;
current->link = p->link;
delete p;
return ture;
}